Optimal. Leaf size=106 \[ -\frac {64 c^3 d^3 \sqrt {d \csc (a+b x)}}{15 b \sqrt {c \sec (a+b x)}}+\frac {16 c d^3 \sqrt {d \csc (a+b x)} (c \sec (a+b x))^{3/2}}{15 b}-\frac {2 c d (d \csc (a+b x))^{5/2} (c \sec (a+b x))^{3/2}}{5 b} \]
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Rubi [A]
time = 0.11, antiderivative size = 106, normalized size of antiderivative = 1.00, number of steps
used = 3, number of rules used = 3, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {2705, 2706,
2699} \begin {gather*} -\frac {64 c^3 d^3 \sqrt {d \csc (a+b x)}}{15 b \sqrt {c \sec (a+b x)}}+\frac {16 c d^3 (c \sec (a+b x))^{3/2} \sqrt {d \csc (a+b x)}}{15 b}-\frac {2 c d (c \sec (a+b x))^{3/2} (d \csc (a+b x))^{5/2}}{5 b} \end {gather*}
Antiderivative was successfully verified.
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Rule 2699
Rule 2705
Rule 2706
Rubi steps
\begin {align*} \int (d \csc (a+b x))^{7/2} (c \sec (a+b x))^{5/2} \, dx &=-\frac {2 c d (d \csc (a+b x))^{5/2} (c \sec (a+b x))^{3/2}}{5 b}+\frac {1}{5} \left (8 d^2\right ) \int (d \csc (a+b x))^{3/2} (c \sec (a+b x))^{5/2} \, dx\\ &=\frac {16 c d^3 \sqrt {d \csc (a+b x)} (c \sec (a+b x))^{3/2}}{15 b}-\frac {2 c d (d \csc (a+b x))^{5/2} (c \sec (a+b x))^{3/2}}{5 b}+\frac {1}{15} \left (32 c^2 d^2\right ) \int (d \csc (a+b x))^{3/2} \sqrt {c \sec (a+b x)} \, dx\\ &=-\frac {64 c^3 d^3 \sqrt {d \csc (a+b x)}}{15 b \sqrt {c \sec (a+b x)}}+\frac {16 c d^3 \sqrt {d \csc (a+b x)} (c \sec (a+b x))^{3/2}}{15 b}-\frac {2 c d (d \csc (a+b x))^{5/2} (c \sec (a+b x))^{3/2}}{5 b}\\ \end {align*}
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Mathematica [A]
time = 0.20, size = 57, normalized size = 0.54 \begin {gather*} -\frac {2 c d^3 \left (-5+32 \cos ^2(a+b x)+3 \cot ^2(a+b x)\right ) \sqrt {d \csc (a+b x)} (c \sec (a+b x))^{3/2}}{15 b} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 55.84, size = 64, normalized size = 0.60
method | result | size |
default | \(\frac {2 \left (32 \left (\cos ^{4}\left (b x +a \right )\right )-40 \left (\cos ^{2}\left (b x +a \right )\right )+5\right ) \cos \left (b x +a \right ) \left (\frac {d}{\sin \left (b x +a \right )}\right )^{\frac {7}{2}} \left (\frac {c}{\cos \left (b x +a \right )}\right )^{\frac {5}{2}} \sin \left (b x +a \right )}{15 b}\) | \(64\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 3.17, size = 89, normalized size = 0.84 \begin {gather*} -\frac {2 \, {\left (32 \, c^{2} d^{3} \cos \left (b x + a\right )^{4} - 40 \, c^{2} d^{3} \cos \left (b x + a\right )^{2} + 5 \, c^{2} d^{3}\right )} \sqrt {\frac {c}{\cos \left (b x + a\right )}} \sqrt {\frac {d}{\sin \left (b x + a\right )}}}{15 \, {\left (b \cos \left (b x + a\right )^{3} - b \cos \left (b x + a\right )\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 2.32, size = 112, normalized size = 1.06 \begin {gather*} \frac {16\,c^2\,d^3\,\sqrt {\frac {c}{\cos \left (a+b\,x\right )}}\,\sqrt {\frac {d}{\sin \left (a+b\,x\right )}}\,\left (5\,\cos \left (a+b\,x\right )-3\,\cos \left (3\,a+3\,b\,x\right )-4\,\cos \left (5\,a+5\,b\,x\right )+2\,\cos \left (7\,a+7\,b\,x\right )\right )}{15\,b\,\left (\cos \left (2\,a+2\,b\,x\right )+2\,\cos \left (4\,a+4\,b\,x\right )-\cos \left (6\,a+6\,b\,x\right )-2\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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